Question

A converging lens with a focal length f1 = 9.00 cm is located 18.0 cm to the left of a converging lens with index of refraction of 1.52 and a radius R = 6.24 cm. An object stands 14.0 cm to the left of the first lens in the combination. Draw the Ray diagrams! (a) Locate the final image relative to the lens on the right. (b) Obtain the overall magnification. (c) Is the final image real or virtual? With respect to the original object, (d) is the final image upright or inverted and (e) is it larger or smaller?

Answer 1

fi f₂ 14cm 36 cm 1 cm 25.2 cm

d S : 18 cm +gm 7, = 152 R₂ - G.24 Cm 2 (nl) (, + + 2 ) (1.52 -1) (24) 1 나 2 나 =+6cm 2. (a) fen I 한 lens u= - 14 Cm - - - He to - -14 14 - 9 - 9 14 14 X9 D = +25.2 Cm for and lens u2 -- (D-d) - - (25·2-18) 2. 카.2Cm - - -2.2 2 12,15 아 - 2 - || 6 구2 2 7·2X6 날 = 36CM (6) M= M,ML = V * MA 252 -14 -구·2 M: 9

(C) with respect to coriginal object final image is virtual. (d) final Image is upright. (e) final Image larger