Question

3.1.0639365 For the forces acting on the beam shown in Figure 3.1g, determine the location of the equivalent resultant force with reference to point A in m. Given / = 1.8, w1 = 15, w2 = 8, P1 = 8 and P2 = 16. (Note: Prefix the value with negative sign "-"if the location is to the left of the reference point. E.g. if the location of the equivalent resultant is located between points A and B, or to the left of point B by 1.2m, the answer should be "-1.2" with reference to point B) W, kN/m P, KN B P2 kN W2 kN/m I m I m Figure 3.18

Answer 1

KN/m الي Pi KN B. Ws kolm. P2 KN WI= 15; We = 8 d=1.8m) Pi=8; P2 = 16 kao

taking moments A: TMA => MA = Pixel + (G x wit x wi x2)x) Paxl - [x ( 4 x W xal x 2) . = 8x3.6 of (e 6x15x3,6x ") 16x1.8 - ( 1 x eo ox 3.6% = (28.8 +13.5–28.8 – 19.28.) IMA I -3.78 kNm X 3.78 knm ( a.ca). al Fig ③ X PA - 9.6 kN

3 For equations of equilibrium: Ify u. Force + downward furce) { (cup ward ~ 6 x 15x3•6) + 18 – (£x8*3.6) - 16. all RA=0 21 +8 - 14.4-16 ORA - 0. force) =RA. on 4-6 KN (down ward RA 4-6 KN TO calculate equilibrium equivalent resultant should be balan cod. force, the moments at created as mement Ř (developed by the applied wads) should be equal to the moment created Reaction force RA. EMA = RAXA. foom Fig ®] Yo 6x2 3,78 = E d=0.8217 m.