int i = 33;
double d = 12.88;
int * iPtr = &i;
double * dPtr = &d; //
iPtr = &d; //
dPtr = &i; //
iPtr = i; //
int j = 99;
iPtr = &j; //
int i = 33; // An int variable with a value
double d = 12.88; // An double variable with a value
int * iPtr = &i; // Declared a pointer variable called iPtr pointing to an int (or int pointer) and Assign the address of the variable number to pointer iPtr
double * dPtr = &d; // Declared a pointer variable called dPtr pointing to an double (or double pointer)
// Assign the address of the variable number to pointer dPtr
iPtr = &d; //Assign the address of the variable number to pointer iPtr
dPtr = &i; //Assign the address of the variable number to pointer dPtr
iPtr = i; //Assign variable number to pointer iPtr
int j = 99;//declared j int variable
iPtr = &j; // assign the address of variable to pointer iPtr
Look at the following code and comment each line about how it works with pointer. int...
[C++ Language] Look at the following code and comment each line about how it works with pointer. int i = 33; double d = 12.88; int * iPtr = &i; double * dPtr = &d; // iPtr = &d; // dPtr = &i; // iPtr = i; // int j = 99; iPtr = &j; //
The following code snippet is for C++ int selection_Sort(int A[ ], int n) { int I, j, small, temp; for( i = 0; i < n-1; i++) { small = i; for(j = i + 1; j < n; j++) { if ( A[ j ] < A[ small ] small = j; } temp = A [ i ]; A[ i ] = A[small]; A[small] = temp; } } Please explain in rich detail the logic behind every execution...
Given the following Java code: class C { public int foo(C p) { return 1; } } class D extends C { public int foo(C p) { return 2; } public int foo(D p) { return 3; } } C p = new C(); C q = new D(); D r = new D(); int i = p.foo(r); int j = q.foo(q); int k = q.foo(r); (Remember that in Java every object is accessed through a pointer and that methods...
Translate the following code into MIPS code. Test (int i, int j) { int k; k = Double(i+1) + Double (j-10) return k; } Sub (int m) { int g; g = m + m; return g; } Assume the compiler associates the variable k to the register $s0. Assume the compiler associates the variable g to the register $t0.
Question 2 (a) Provide a single line of C++ code that will declare a variable that points to a string value, the variable is named x. [2 marks] (b) You have array c declared as string *c [5]; Give the single line of C+ + code that will assign the string pointer stored in variable x (from above) to the third element of the array c. [2 marks] (c) Write a for loop that initialises the contents of each element...
The following lines of code all have problems. Identify what
is wrong with each line of code
The following lines of code all have problems. Identify what is wrong with each line of code. a) for(j=0; j<= 10; j++) cout << prices[j]; b) int array = {1,2,3,4}; c) int arr[3]; for (arr = 0; arr < = 10; arr++) d) char k; for (k=0; k<= 10; k++)
Show how to get the big-Oh for the following code: void CountSort (int A[N], int range) { // assume 0 <= A[i] < range for any element A[i] int *pi = new int[range]; for ( int i = 0; i < N; i++ ) pi[A[i]]++; for ( int j = 0; j < range; j++ ) for ( int k = 1; k <= pi[j]; k++ ) cout << j << endl; }
Please explain how these code run for each line #include<stdio.h> #include<string.h> /** * Part A */ struct myWord{ char Word[21]; int Length; }; int tokenizeLine(char line[], struct myWord wordList[]); void printList(struct myWord wordList[], int size); void sortList(struct myWord wordList[], int size); /** * main function */ int main() { struct myWord wordList[20]; char line[100]; printf("Enter an English Sentence:\n"); gets(line); int size = tokenizeLine(line, wordList); printf("\n"); printf("Unsorted word list.\n"); printList(wordList, size);...
7. The code segment given sorts an array. Show how this works on the given array by redrawing the array each time one of the entries changes value. const int IsizeĀ·6; // list size int list [lsize]; int j, x; for (int i = !size-1; i > 0; i-) { x = list [i]; ji; for (int k = i-1 ; k >= 0; k-) { if (list [k] > x) f j -k; x = list(k); list [j] list...
Explain the following code, line by line. As well as the is going on over all. #include <stdio.h> int main() { int a[30]; int i,j,lasti; int num; lasti=0; // scanf the number scanf("%d",&a[0]); while (1) { // sacnf the new number printf("Enter another Number \n"); scanf("%d",&num); for(i=0;i<=lasti;i=i+1) { printf("%d \n",a[i]); // we check if the num that we eneterd is greter than i if(a[i] > num) { for(j=lasti; j>= i;j--) { a[j+1]=a[j]; } a[i]=num; lasti++; break; } }...