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Suppose that the parents of a young child decide to make annual deposits into a savings account, with the first deposit being

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Answer #1

Assume that annual deposit = X

Amount of withdrawls mentioned in diagram:

18th Year= $2,000

19th Year= $2,400

20th year= $2,800

21st year= $3,200

We first need to find Present worth of total deposit at the end of the year of 18th year:

= $2,000 + [$2,400 x (PVF, 4%, 1 year)] + [$2,800 x (PVF, 4%, 2 year)] + [$3,200 x (PVF, 4%, 3 year)]

= $2,000 + $2,307.69 + $2,588.75 + $2,844.78

= $9,741.22

$9,741.22 this is the size of deposit of 18th year, which is due to annual deposits made between year (5-15).

Again find the Present worth of size of deposit $9,741.22 at the end of the year 18th year:

PW of deposit at EOY 15th year = $9,741.22 x PVF @ 4% for 3 years

= $8,659.91

Now these annual deposits made between year 5 to year 15:

X (PVF @ 4% for 10 years) = $8,659.91

Time duration is between 15 - 5 =10 years

X (8.1109) = $8,659.91

X = $1,067.69

...

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