This week, a very large running race (5K) occured in Denver. The
times were normally distributed, with a mean of 20.91 minutes and a
standard deviation of 2.17 minutes.
Report your answers accurate to 2 decimals
a. What percent of runners took 16.5 minutes or less to complete
the race? %
b. What time in minutes is the cutoff for the fastest 10.65
%? Minutes
c. What percent of runners took more than 15 minutes to complete
the race? %This week, a very large running race (5K) occured in
Denver. The times were normally distributed, with a mean of 20.91
minutes and a standard deviation of 2.17 minutes.
Report your answers accurate to 2 decimals
a. What percent of runners took 16.5 minutes or less to complete
the race? %
b. What time in minutes is the cutoff for the fastest 10.65
%? Minutes
c. What percent of runners took more than 15 minutes to complete
the race? %
Define random variable X: The time taken by runner to complete the race
X follows normal distribution with mean = = 20.91 and standard deviation = = 2.17
a)
Here we have to find
where z is standard normal variable
(Round to 2 decimal)
= 0.0212 (From statistical table of z values)
2.12% of runners took 16.5 minutes or less to complete the race.
b)
We have to find x such that P(X > x) = 0.1065
1 - P(X < x) = 0.1065
P(X < x) = 0.8935
z for area = 0.8935 is
z = 1.25 (From statistical table of z values)
x = 20.91 + 2.702428
x = 23.61 (Round to 2 decimal)
23.61 minutes is the cutoff for the fastest 10.65%
c)
Here we have to find
where z is standard normal variable
(Round to 2 decimal)
= 1 - P(z < -2.72)
= 1 - 0.0033 (From statistical table of negative z values)
= 0.9967
99.67% of runners took more than 15 minutes to complete the race.
This week, a very large running race (5K) occured in Denver. The times were normally distributed,...
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