Question

Problem 2 [22 Points, 2 Each] The figure below shows a plate with flatness applied to the top surface. The thickness of the plate is also being controlled. For the actual sizes of the plate thickness provided in the table below, determine the allowable flatness of the feature. 0.002 1.75040.005 Actual Size Allowable Form Tolerance 1.75 1.70 1.750 1.151

Answer 1

Given :- Thickness of the plate Plate = 1.750 t o.oos Flatness allowance 0.002 0.002 1.750F 0.005 To find : Allowable form Tolerance in the given Dimension of the thickness solution : → Allowable form tolerances (Mascimum Material Limit - Acheial size) t form Tolerance Here in the question MML Maximum Malesial Limit 1.750 + 0.005 1.755 Form Tolerance = 0.002

(MML- Actual size) + Form Tolerance fom Tolerance = (1.755-1.755)+0.002 :. For, actual size = 1.745 Allowable Form Tolerance = (1.755 1.745) + 0.00 2 0.012 For, Actual size 1.749 Allowable foom Tolerance = (1.749 -1.745) +0.002 For Actual size = 0.006 = 1.755 Allowable = 0.002 Actual size Allowable Form Tolerance 2 3 1.745 1.746 1.747 1.748 1.749 4 S C1.755-1.74.5) +0.002 = 0.012 C1:755-1.746) to.002= 0.011 (1:755 -1.747) +0.00230.010 Cli7552_1:748) + 0.0022 0.009 (1.755 - 1.749)+ 0.002 = 0·008 (1.755- 1:750) + 0.002 = 0.007 (1.756- 1.750 + 0.002 -0.006 (1:755-1752) +0.002 = 0.005. (1:755 - 1:753) +0.002 = 0:00h (1.755-1.754 t 0.002 = 0.003 (1.755-1.755) + 0.002 -0.002 6 그 1.750 1.751 1-752 1:753 8 9 lo 1.754 1.755