Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to flip the coin in order to obtain a 98% confidence interval of width of at most .19 for the probability of flipping a head?
a) 150
b) 149
c) 117
d) 116
e) 152
Solution :
=> Answer :- Option a) 150
Given that width w = 0.19
=> Margin of error E = w/2
= 0.19/2
= 0.095
=> For 98% confidence interval, Z = 2.326
=> p = 0.5, q = 1 - p = 0.5
=> Sample size n > p*q*(Z/E)^2
n > 0.5*0.5*(2.326/0.095)^2
n > 149.8691
=> n = 150 (nearest integer)
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