Question

75kp/tt 15 kip 6 kip/ 12- A 6 3 121 For the Beam show ease answer the following ustions regarding the sheardgam The Shear just to the Right The Shearlust the list! Vip The Shear just to the right of The Sheart to the left of le The Shearlast to the right of isip The Shear just to the left of Dis et lap Shade of spen AB Set Shape of span BC! Shape of spen CES For the Benshowever the following cuestions regarding the Moment diagram The Moment kust to the left of BB! The Moment just to the right of Bisel The Moments to the left of Cisteet ✓ Kept The Moment just to the right of Kip-ft Shape of Moment for an ABS Shape of Moment for sans le Shape of Moment for sen CE is see Shape of Moment for scan Disie Maximum Positive Momentet Kot Maumumnegative Moment Kip-

Answer 1

7.5 kipler 15kip 6 Kiplft. A for से 75 Kip-ft 6S+ 881 12 ft FBD: 0.5x6 x7.5 =(22.5) (6X12).=(72) 15 kip Go Rax Ray 75 kip-St. Ro. 32 2t 4 PL. oft E oft SED: 33.79 Кір. 26.29 kip 11.29 Kie A B E D х - 45.71kg BMD. 191.57 174.15 112.71 116:57 A B CS Scanned with CamScanner

Reactions zo O Ray tve Efy + Ro 22.5 +15 – 72 : .. Ray+Ro = 79.5 kip EMA 22.5x2 + 15X6 + 75 - 72x15 -Rox 20 : Ro=+45 71 kip Ray = 33.79 kip from c Roy=o) JO Shear force diogram : Calcolations chlagre + slept right SFA SFAT SFB SF B t = SFC SED SFpt = 33.79 kip 33.79 - 22.5 - 11.29 Kip 11.29 + 15 26-29 kip 26-29 KIP 26.29 - 72 →-45.71 kip 1) o O BMD: ce is the . 26.29 = To find: ex Using Similarly traingular role: 45.71 C12-x) : (x=4.38160 ft) x CS Scanned with CamScanner

BMA= BMD=0 BMB = Roy X 6 - 22.5x4 → 112.71 Kip-ft BMc Ray x 9 - 22.5x 7 + 15x3- 191.01 kipfi BMct 191.61-75- 116.61 kipere BME = Rex C12-4-38160). 6 C12-4.38160)2 2 174.117 Kip-ft Max shea Max BM 145.71 kipl 191.01 Kip-ft CS Scanned with CamScanner