Question

MY NOTES ASK YOUR TEACHER PRACTICE ANOTHE (-/2. Points) DETAILS SERCP113.2.OP.015. In an online viral video, a van rolls down an incline and off a vertical dift, failing into an ocean below. The van starts from rest and roll down the incline, which makes an angle of 25.0 below the horizontal with a constant acceleration of 3.97 m/s? Aher rolling down the indine a distance of 35.0 m, it reaches the edge of the cliff, which is 30.0 m above the ocean (a) How much time (ins) does it take the van to fall from the edge of the diff to the landing point? (b) At the point where the van lands in the ocean, how far is it horizontally from the edge of the cit (in) m

Answer 1

Ans" - at edge of For velocity celiff v2=42+zas => vz=o+2(3.9735 riv- 16.67 mles 25-> Vcog (25) vsin (25) 300m motion in y-direction S = ut + hat? 30= 16.67 sin(25%) it + 1x9.842 7.045+tqogt2 => 4.9 t²+7.045f-300 -7.045 t (7.045) ² - 4x4.9% (-30) 5 = 1) = 2x qog - 7.045 t 25.25 9.8 180205 c one root exalege because 9.8 of ime can't Negative) 1.857 rec Horizontal distance of landing Point from Cliff - vcos (250) Xt 16.67 cos (250) x 1.857 28.05 m (6)