Question

Calculate the final temperature for a solution that has 25g of H2O at 15° from 45g of H2O at 50° and from 15g of H2O at 37°.

thank you in advance

No i think that's i dont have grammatical mistakes and i have this solution but i dont sure that’s true

* The energy amount going out of the is equal to the energy- amoure going into the cool. It indicates cu arm water Glest = ggain mx XAT cm x CxA7 mg x (Ta - To = m, CT, -Tp) tma(135) m3 =25g ma=45g m = 15g. T2=? T,=37°c Iz=500 T4 = 150 25% (T2-152 = 15x(37–53) + 45 (50-T2) 25 T2 - 375 =555-15T2+ 2250 - 45T 25 Ta + 15 Tq +45T2 - 3250 +555 +375 55TQ = 3180 Tz 85 = 3180 137.40

Answer 1

solution : $9 че 8 ho 12o Тегия 7,50 Ti-37°c mix to each other 5 659 м. fined: 2 А , т 84 Т. * <em : о or q last I gain A specific heat capacity + E) 24хх (1 - ) 22s (1 -1) чо А(. - (o') + (х4 (1 Дs 4 (1, - сә) + че (Т, те) + (1, 211*) со 41, чут, Lif1, 2 Чү If + чухо +1(x 17 а) % 1, 2 310 1, 2 11 КО K : 37 •Ч А.