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a The length of time (in years) until a particular radioactive particle decays is a random variablet with probability density

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ANSWER:0 - ey even that :- f (t)=8 est fort in ay Now; Let {1+)= 8.2-8t te [0,0) tse it at EL?).- Polana au e da -st dt té P MP 8 12P( Between mean and 9 standard deveation above the mean) - PLOCT($) 78 . est sie at 0 [-e -engt 7/8 O ine § 1-036 7819 0.632111 1094-1) 게 902y M 22 21 s 10 2 -1 M pe Variance o² = ( 2² f(x) dx ee2 302 22통d 20192 1 302 &모da - Youl ) 14 90 야 (J- SS [Ca@ - 4.81 333 -4.41 0.403335 02 = 0.40833 o 0.6350826 standard deviation (0.) = 006351 & cooby 0.64 is f 5 da 11 2.1 5 Il [226 C) PLZZZ) = 20 0/0 P( 222) 50020 P[z (-0.8416] - 020 Z .0.84.16 2= -0.8 - 0 • ៩ ។ (pounded) standard .: using Nooma! table]

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