If 5.25 mL of a 0.278 M solution of NaOH is required to neutralize 15.7 mL of a HCl solution, What is the concentration of the HCl solution?
Select one:
a. 15 M
b. .450 M
c. 0.0930 M
d. 0.555 M
NaOH reacts with HCl and produces H2O and NaCl.
The balanced reaction is :
NaOH + HCl ----> NaCl + H2O
Therefore, 1 mol of NaOH reacts with 1 mol of HCl.
No. of mol of NaOH = molarity x volume in L
= 0.278 mol/L x 0.00525
L
= 1.4595 x 10-3 mol
Therefore, we need 1.4595 x 10-3 mol of HCl to
neutralize the NaOH.
Molarity = no. of mol/ volume in L
= 1.4595 x 10-3 mol /
0.0157 L
= 0.0930 mol/L
= 0.0930 M
Hence, the molarity of HCl = 0.0930.
Answer = C(0.0930 M)
If 5.25 mL of a 0.278 M solution of NaOH is required to neutralize 15.7 mL...
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