Homework Answers
At 300K, the concentration of sample in 4th day= 0.15M
From the table concentration decrease by 0.15M each day. So, for 0.2 part of a day, the decrease in concentration = 0.15×0.2= 0.03
Therefore, the concentration of sample after 4.2 days= 0.15-0.03= 0.12M
So, the last option is the right answer.
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