slide has an angle of 35 degrees. the coefficient of kinetic friction between the person and the surface of the slide is 0.1. what is the magnitude of acceleration of a person sliding down the slide?
Here ,
theta = 35 degree
u = 0.10
magnitude of acceleration = g * (sin(theta) - u * cos(theta))
magnitude of acceleration = 9.8 * (sin(35 degree) - 0.10 * cos(35 degree))
magnitude of acceleration = 4.82 m/s^2
the magnitude of acceleration is 4.82 m/s^2
slide has an angle of 35 degrees. the coefficient of kinetic friction between the person and...
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