Question

A 95 kg patient swallows a 34 ?Ci beta emitter whose half-life is 5.0 days and...

A 95 kg patient swallows a 34 ?Ci beta emitter whose half-life is 5.0 days and whose RBE is 1.6. The beta particles are emitted with an average energy of 0.35 MeV, 90% of which is absorbed by the body.

You are a health care worker needing to find the patient's dose equivalent after one week. These series of steps will help you find that dose equivalent. In all questions, assume the radioactive nuclei are distributed throughout the patient's body and are not being excreted

Part A: How many radioactive nuclei did the patient swallow?  

N0 = 7.84x10^11

Part A: How many radioactive nuclei did the patient swallow?  

N = 2.97x10^11

Part C

How many radioactive decays occured in the patient during the first week?  

0 1
Add a comment Improve this question Transcribed image text
Answer #1

Az 34 uci = 34610-6Ci =(34X10-9 (3.7x100) =1258x1dfeq;ty2 = Sder ca Rot 1/2 (1* 258X106) (5 X 24X60X60) ena 7. 848 10 No= Rb) N = No (0.5t/t1/2 > 7.84XLO (0.5) 715 N = 2.97% 10HRadioactive nuclei occurred in week first NO -N =No (1-(1) 75) = 7.84X10(1-10)53) ND = 4.878 holl

Add a comment
Know the answer?
Add Answer to:
A 95 kg patient swallows a 34 ?Ci beta emitter whose half-life is 5.0 days and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT