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Determine the rate constant and ultimate BOD from the following data: (3 oints Time (day) (mg/L)...
1. (30 points) Determine the 1-day BOD (BOD) and ultimate CBOD (BOD, or Lo) for a...
1. (30 points) Determine the 1-day BOD (BOD) and ultimate CBOD (BOD, or Lo) for a wastewater whose 5-day BOD at 20 °C is 200 mg/L, when -0.23 day.
2. A 5-day BOD of a sample was determined to be 250.0 mg/L and the rate...
2. A 5-day BOD of a sample was determined to be 250.0 mg/L and the rate constant is 0.35 d. What is the ultimate BOD of the sample?
QUESTION 5 5.1 Determine the 4-day BOD and the Ultimate BOD (1st stage) for a wastewater...
QUESTION 5 5.1 Determine the 4-day BOD and the Ultimate BOD (1st stage) for a wastewater whose BODs at 20 °C is 250 mg/l. The reaction constant is k=0.23d" (base e). Determine the BODs if the test had been done at 25 °C. (10) 5.2. The chlorination unit in a WWTP uses 10 containers of chlorine on a monthly basis. A chlorine dosage is 4 mg/l is used to treat an average monthly wastewater effluent of 500 000 mDetermine the...
(20 pts) The ultimate BOD of a domestic wastewater is 275 mg/L and the e based...
(20 pts) The ultimate BOD of a domestic wastewater is 275 mg/L and the e based rate constant k=0.24 d a. (4 pts) What will be the 5-day BOD (Sample-1)? b. (4 pts) What will be the 7-day BOD? (Sample-1)? c. (4 pts) A different sample has the same ultimate BOD given in the question, but the 20 °C k value (e based) is equal to 0.36 dl Determine the 5-day BOD of this sample (Sample-2). d. (8 pts) Please...
Calculate the BOD Ultimate value given the following information BOD5= 316 mg/L k = 0.23 day-1...
Calculate the BOD Ultimate value given the following information BOD5= 316 mg/L k = 0.23 day-1 Temperature is 20 C for both BOD5 and BOD Ultimate (L)
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L...
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L at 20 oC. The reaction rate k at that temperature has been determined to be 0.2/day. a) Find the BOD5. b)Find the reaction rate coefficient at 15 oC. c) Find BOD5 at 15 oC. O 132 mg/L, 0.18/day, 265 mg/L O 190 mg/L, 0.16/day, 165 mg/L O90 mg/L, 0.16/day, 245 mg/L O 232 mg/L, 0.18/day, 365 mg/L
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted;...
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted; data are summarized in the table below. Ten mL of wastewater was added per 300 mL bottle to determine the dissolved oxygen demand of the aged, settled wastewater seed (test A). The seeded test bottles (test B) contained 2.5 mL of industrial wastewater and 1.2 mL of seed wastewater a) What is the five-day BOD in this industrial wastewater? What is the k-value using...
7. You work for the Ministry of Environment to evaluate the maximum ultimate BOD concentration in...
7. You work for the Ministry of Environment to evaluate the maximum ultimate BOD concentration in the effluent of a new wastewater treatment plant such that the oxygen deficit never exceeds 1.5 mg/L in the receiving river. During dry weather (i.e., lowest river flow), the wastewater will be diluted 10 times in the river water and the river water contains 3.5 mg/L of ultimate BOD. Also during dry weather, you know that the river velocity after the wastewater discharge would...
\The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The...
\The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The design solids concentration (X) at steady-state is 2,000 mg/L. The design MCRT is 7 days. The kinetic coefficients are as follows: k = 2 g BOD/g cells*day; Ks = 25 mg BOD/L; kd = 0.06 1/day; Y = 0.5 g cells/g BOD. The influent ammonia concentration is 40 mg/L and nitrification is needed. It takes 1400 ft3 of air per pound of BOD. Use...
Determination of BOD dilution
Consider the BOD data below (no dilution,no seed). a. What is the ultimate carbonaceous BOD? b. What might have caused the lag at the beginning of the test? c. Calculate k’, (the reaction rate constant). Day DO(mg/L) ~~ 0 8 1 8 3 75 6.5 7 6 15 ...
1. (30 points) Determine the 1-day BOD (BOD) and ultimate CBOD (BOD, or Lo) for a wastewater whose 5-day BOD at 20 °C is 200 mg/L, when -0.23 day.
2. A 5-day BOD of a sample was determined to be 250.0 mg/L and the rate constant is 0.35 d. What is the ultimate BOD of the sample?
QUESTION 5 5.1 Determine the 4-day BOD and the Ultimate BOD (1st stage) for a wastewater whose BODs at 20 °C is 250 mg/l. The reaction constant is k=0.23d" (base e). Determine the BODs if the test had been done at 25 °C. (10) 5.2. The chlorination unit in a WWTP uses 10 containers of chlorine on a monthly basis. A chlorine dosage is 4 mg/l is used to treat an average monthly wastewater effluent of 500 000 mDetermine the...
(20 pts) The ultimate BOD of a domestic wastewater is 275 mg/L and the e based rate constant k=0.24 d a. (4 pts) What will be the 5-day BOD (Sample-1)? b. (4 pts) What will be the 7-day BOD? (Sample-1)? c. (4 pts) A different sample has the same ultimate BOD given in the question, but the 20 °C k value (e based) is equal to 0.36 dl Determine the 5-day BOD of this sample (Sample-2). d. (8 pts) Please...
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L at 20 oC. The reaction rate k at that temperature has been determined to be 0.2/day. a) Find the BOD5. b)Find the reaction rate coefficient at 15 oC. c) Find BOD5 at 15 oC. O 132 mg/L, 0.18/day, 265 mg/L O 190 mg/L, 0.16/day, 165 mg/L O90 mg/L, 0.16/day, 245 mg/L O 232 mg/L, 0.18/day, 365 mg/L
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted; data are summarized in the table below. Ten mL of wastewater was added per 300 mL bottle to determine the dissolved oxygen demand of the aged, settled wastewater seed (test A). The seeded test bottles (test B) contained 2.5 mL of industrial wastewater and 1.2 mL of seed wastewater a) What is the five-day BOD in this industrial wastewater? What is the k-value using...
7. You work for the Ministry of Environment to evaluate the maximum ultimate BOD concentration in the effluent of a new wastewater treatment plant such that the oxygen deficit never exceeds 1.5 mg/L in the receiving river. During dry weather (i.e., lowest river flow), the wastewater will be diluted 10 times in the river water and the river water contains 3.5 mg/L of ultimate BOD. Also during dry weather, you know that the river velocity after the wastewater discharge would...
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