Question

/*

•   The following code consists of 5 parts.
•   Find the errors for each part and fix them.
•   Explain the errors using comments on top of each part.

*/

#include <stdio.h>
#include <string.h>

int main( ) {

//////////////////////////////////////////////////////////////////////////
//////////////        Part A. (5 points)                //////////////////

int g(void)
{
printf("%s", Inside function g\ n " );
int h(void)
{
      printf(" % s ", Inside function h\ n ");
}
}

printf("Part A: \n ");
g();
printf(" \n");

//////////////////////////////////////////////////////////////////////////
//////////////        Part B. (5 points)                //////////////////

int sum( int x, int y )
{
int result;
result = x + y;
}

printf("Part B: % d \n", sum(5,3));

//////////////////////////////////////////////////////////////////////////
//////////////        Part C. (5 points)                //////////////////

void f( float a );
{
   float a;
   printf( "%f", a );
}

printf("Part C: % 1f \n", f(1.1));

//////////////////////////////////////////////////////////////////////////
//////////////        Part D. (5 points)                //////////////////

#include <stdio.h>
#include <string.h>

int main( ) {

int sum( int n )
{
if ( 0 == n )
{
    return 0;   
}
else
{   
    n + sum( n - 1 );
}
}

printf("Part D: % d \n", sum(3));
return 0;
}

//////////////////////////////////////////////////////////////////////////
//////////////        Part E. (5 points)                //////////////////

void product( void )
{
int a, b, c, result;
printf( "%s", "Enter three integers: " )
scanf( "%d%d%d", &a, &b, &c );
result = a * b * c;
printf( "Result is: %d", result );
return result;
}

printf( "Part E: %d", product ());

return 0;
}

Answer 1

////////////////////////////////////////////////////////////////////////// //////////////        Part A. (5 points)                ////////////////// int g(void) { printf("%s", Inside function g\ n " ); int h(void) {       printf(" % s ", Inside function h\ n "); } } printf("Part A: \n "); g(); printf(" \n"); ////////////////////////////////////////////////////////////////////////// In part one error is becase of printf("%s", Inside function g\ n " ); here we are trying to print string but Inside function g\ n " it is not a string string should in betwenn " and " so correct syantax is printf("%s"," Inside function g\ n " ); for part 1 correct code is: ////////////////////////////////////////////////////////////////////////// //////////////        Part A. (5 points)                //////////////////    int g(void)    {       printf("%s", "Inside function g\ n " );       int h(void)       {           printf(" % s ", "Inside function h\ n ");       }    }       printf("Part A: \n ");    g();    printf(" \n"); ////////////////////////////////////////////////////////////////////////// //////////////        Part B. (5 points)                //////////////////

There is know error in part B.Everything works fine

void f( float a ); {    float a;    printf( "%f", a ); } printf("Part C: % 1f \n", f(1.1)); In part c there lot of error 1)void f( float a ); here we are trying to create a function f but we are put ; at the end so it doesn't act as a function it acts as a statement so we have to remove semicolon 2)float a; we are alredy passing a as an argument so it leads to redeclaration to avoid this eirther we have to remove float a from functino body or we have to change it's name. 3)printf("Part C: % 1f \n", f(1.1)); here we are trying print the return value of f(float a).But the return values is void.so we have to change it to float. Part C: float f( float a ) {    printf( "%f", a );     return a; }    printf("Part C: % 1f \n", f(1.1));

D) There is no error in part D internally.But if we observe it it has a main method. we are writing part D inside a main method.A c programm doesn't contain two main methods. we can resolve it by 1) writing part D in a separate file

void product( void ) { int a, b, c, result; printf( "%s", "Enter three integers: " ) scanf( "%d%d%d", &a, &b, &c ); result = a * b * c; printf( "Result is: %d", result ); return result; } printf( "Part E: %d", product ()); In part E 1) printf( "%s", "Enter three integers: " ) there is no semicolon at the end so insert ; at the end. 2)void product( void ) here we are returning void but return result; in function body we are returning an int type. so change it return type to int. int product(void); Part E: int product( void ) { int a, b, c, result; printf( "%s", "Enter three integers: " ); scanf( "%d%d%d", &a, &b, &c ); result = a * b * c; printf( "Result is: %d", result ); return result; } printf( "Part E: %d", product ()); return 0;

//entire code for part a,b,c,e #include <stdio.h> #include <string.h> int main( ) { ////////////////////////////////////////////////////////////////////////// //////////////        Part A. (5 points)                ////////////////// int g(void) { printf("%s", "Inside function g\ n " ); int h(void) {       printf(" % s ", "Inside function h\ n "); } } printf("Part A: \n "); g(); printf(" \n"); ////////////////////////////////////////////////////////////////////////// //////////////        Part B. (5 points)                ////////////////// int sum( int x, int y ) { int result; result = x + y; } printf("Part B: % d \n", sum(5,3)); ////////////////////////////////////////////////////////////////////////// //////////////        Part C. (5 points)                ////////////////// float f( float a ) {    printf( "%f", a ); } printf("Part C: % 1f \n", f(1.1)); //////////////        Part E. (5 points)                ////////////////// int product( void ) { int a, b, c, result; printf( "%s", "Enter three integers: " ); scanf( "%d%d%d", &a, &b, &c ); result = a * b * c; printf( "Result is: %d", result ); return result; } printf( "Part E: %d", product ()); return 0; }

////////////////////////////////////////////////////////////////////////// //////////////        Part D. (5 points)                ////////////////// #include <stdio.h> #include <string.h> int main( ) { int sum( int n ) { if ( 0 == n ) {     return 0;    } else {        n + sum( n - 1 ); } } printf("Part D: % d \n", sum(3)); return 0; } //////////////////////////////////////////////////////////////////////////