A) 20.2 ml = 0.0202 L
No. of mole = molarity volume of solution in liter
No. of mole of Ag+ = 0.10.0202 = 0.00202 mole
According to reaction Ag+ and Cl- react in equimolar proportion thus, to to react 0.00202 mole of Ag+ 0.00202 mole of Cl- must be there
molar mass of Cl = 35.453gm/mole that mean 1 mole of Cl = 35.453 gm then 0.00202 mole Cl = 35.4530.00202 = 0.071615 gm of Cl
0.071615 gm of Cl in sample
B) 10 gm mass = 100%
then 0.071615 gm = 1000.071615/10 = 0.71615%
0.71615% of Cl- in solution.
The quantity of Cl in a water supply is determined by titrating the sample with Ag^+...
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