Question

Did I do this problem on lineral thermal expansion correctly? Information was left out of the...

Did I do this problem on lineral thermal expansion correctly? Information was left out of the problem, so I assumed the material to be steel, as iron was not listed in my book.

You are asked to lay a railroad track. Each piece of track is 30.0m long and the temperature in the region varies from -10oF in the winter to to 95oF in the summer. How close can you lay down the successive tracks without causing undue stresses in the track?

My work: -10oF = -23.3o C and 95oF = 35oC; \alpha steel = 1.2x10-5 oC

\Delta L=\alpha L_{o}\Delta T = (1.2x10-5 oC)(30.0m)(58oC) answer = 0.021m

Also, would the numerical value for the coefficient of linear thermal expansion be the same if the temperature was measured in degrees farhenheit?

My answer would be no because 1oF = 5/9 of 1oC. Also, I played around with some values and I got very different answers for \alpha when I used farhenheit. Is this correct?

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Answer #1

Your answer is correct since u have considered coefficient of thermal expansion and the temperature difference both in celcius.

The thermal expansion in fahrenheit scale would have a different value, never the less the answer would remain the same as we again considering the temperature in fahrenheit scale resulting in the same answer

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