Question

2. A laptop computer that costs $1150 new has a book value of $550 after 2 years. (a) Find the exponential model V = aekt (b) What is value of the laptop after 3 years? 3. Suppose you deposit $4000 in an account paying 3.1% interest per year. (a) How much money is in the account after 7 years if the compounded Continuously? A = Pere (b) How long will it take to double your money?

Answer 1

V=gekt Page- Here, N= $550 a $1150 += 2 years, k=? [2] @ 550 = 115002K take en both the sides 2x = ln (5) ak= lnll- In 23 2K = 2.397895273 - 3.135494216 2k = -0.737598943 K= -0-732594943 KE-0-368799471

The Exponential Model is VI = 1150 -0.368799474 t ③ put it = 3 in V (H) V3) = 1150e -0.368799471(3) V3) = 1150e 1106394415 V3) = 1150 (0.33 0748035] N(3) = 380:3602411 the value of the leptop after three years is $ = 380.3602411 = ($380.3602411 Aus

13 Here, A= Pent Page 1 A-$4,000 t = 7 years 8= 3.1% = 3.1 = 0.031 A = ? 700 So. A = 0.03167) 4000 e A = 4000 0.217 A = 4000(1.24-2344102) A-4969.376409 A$ 4969.3769-09) 7 years Hence, the money in the Account after is 4.969.3761-09

double then When the money is A = 2p/ Here, P= $4,000 8 = 3.1% = 3.1 = 0.031 A = 2(4000) = 8000 t = ? 3000= 4.000 0.031(f) 0.0314 8000 = 2 4000 = 2 (0.0314 - 2 take In both the sides 0.034 = ln 2 0-031t = 0.69314718 t-0.69314718 0.031 = 22.35958647 t - 22-35958647 22.4 yeary the money is doable in 22.4 year's ] Hence,