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Problem 2: Consider again the two RLC circuits from HW1 Problem 6 C L IKs IKs...
2) RLC series circuits R1 1m 2 1E-6 V1 C1 1E-12 TR = Ở TF 0 PW = 1 PER = 2 In the above circuit, the voltage source is 5V for t<0 and 10V for t>0 2.1: Draw the s-domain equivalent circuit. Include the intial conditions in your s-domain circuit. Label your component values using symbolic notation (eg. sL1). 2.2: Using impedances, determine the transfer function for the voltage across C1. Use symbolic numbers in your expression. 2.3: Using...
Circuits Spring 2019Name Homework 13 ECSE-2010 Problem 1) Multiple regions, first order L1 R1 100 1E-2 C1 1E-4 R2 100 In the above circuit, Vs-5u(t) Switch U1 is closed at t 0 and opens at t- 15ms Switch U2 is open at t 0 and closes at t- 15ms a. Determine the initial conditions, Vc(0) and dVc(0)/dt. b. Determine the particular solution, Vcp(t) for 0 t< 15ms. c. Determine the voltage across the capacitor, Vc(t), for 0t<15ms. d. Determine the...
1. (30pt) LC Circuit and Simple Harmonic Oscillator (From $23.12 RLC Series AC Circuits) Let us first consider a point mass m > 0 with a spring k> 0 (see Figure 23.52). This system is sometimes called a simple harmonic oscillator. The equation of motion (EMI) is given by ma= -kr (1) where the acceleration a is given by the second derivative of the coordinate r with respect to time t, namely dr(t) (2) dt de(t) (6) at) (3) dt...