solution and explanation please!
Force on 7C due to -3C charge is given by 9*109*7*10-6*3*10-6/22 = 0.04725 N (towards -3C charge)
Force on 7C due to 5C charge is given by 9*109*7*10-6*5*10-6/22 = 0.07875 N (away from 5C charge)
Total horizontal force on 7C is 0.07875-0.04725*cos60 = 0.055125 N (towards right)
Total vertical force on 7C is 0.04725*sin60 = 0.0409 N (vertically upwards)
Resultant force magnitude = sqrt(0.0551252+0.04092)=0.0686 N
solution and explanation please! Equilateral triangle Find the resultant force on the 7uC charge Graded classwork:...
Question6 Three charged particles are located at the corners of an equilateral triangle as shown in figure Calculate the magnitude and direction of the total a) electric force on the 7.00 HC charge and b) electric field on the 7.00 uC charge c) Find the electric potential at the location of the-4.00 μC charge due to the other 2 charges. 7.00 μ C 0.500 m 60.0° 2.00 uC -4.00 uC
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 4.00 μC, and L = 0.800 m.) (a) Calculate the electric field at the position of charge q due to the 7.00-HC and -4.00-uC charges.(b) Use your answer to part (a) to determine the force on charge q.
10. Three point-like charges are placed at the corners of an equilateral triangle as shown in the figure, a -36.0 cm. Find the magnitude of the electric force exerted on the charge q Let q 2.30 uC, q4.00 uC, and ,4.00 HC I N 41 42
help!!!! Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 3.00 μC, and L- 0.950 m.) 7.00 μC 60.0° -4.00 μC (a) Calculate the electric field at the position of charge q due to the 7.00-HC and -4.00-HC charges. 18 Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. kN/C i218 Think carefully about the direction of the field...
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μς, and L = 0.350 7.00 μC 60.0° 4.00 pC (a) Calculate the electric field at the position of charge q due to the 7.00-HC and -4.00-HC charges. kN/Cj b) Use your answer to part (a) to determine the force on charge q.
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q 4.00 μC, and L-0.800 m.) 7.00 μο: 60.0° -4.00 pC (a) Calculate the electric field at the position of charge q due to the 7.00-HC and -4.00-HC charges. kN/Ci + kN/Cj (b) Use your answer to part (a) to determine the force on charge q. mN
Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q - 2.80 uc, and L0.610 ). Calculate the total electric force on the 7.00-yc charge magnitude 114 direction 2993 If you calculate the magnitude of the force that each charge exerts on the 7.00 HC charge, the net charge can then be tound from the vector sum of those forces. N You need the components of the total force in...
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 4.00 μC, and L = 0.350 m.) 7.00 C 60.0 -4.00 pC (a) Calculate the electric field at the position of charge q due to the 7.00-HC and -4.00-HC charges. Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. kN/C i + -445.37 (b) Use your answer to part (a)...
Using the same triangle, find the vector components of the electric force on qi and the vector's magnitude and direction. 6,00 n 12 5.00 m 91 Problem 15.1 (Page 409) A 4.5x 10.9 C charge is located 3.2 m from a-28x 10-9 C charge. Find the electrostatic force that one charge exerts on the other Problem 15.3 (Page 409) An alpha particle (charge +2e) is sent at high speed toward a gold nucleus (charge 79 ) (a) What is the...
The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where +23.0 uC and c7.45 HC. (Assume that the +x-axis is directed to the right.) (a) Find the electric field at the location of q magnitude direction N/C (counterclockwise from the axis) (b) what is the force on q', given that q" = +1.50 nC? magnitude direction 。(counterclockwise from the +x-axis)