Question

Triode region help. PMOS and NMOS . Saturation question. my work is below...did I do this right? I feel I am missing something. Are they both showing saturation?

In the following problems, unless otherwise stated, assume unCox = 200 u A/V, MpCox 100 u A/V, and Vth = 0.4 V for NMOS devices and —0.4 V for PMOS devices. 6.24. In the Fig. 6.42 , what is the minimum allow- able value of Vpp if M1 must not enter the triode region? Assume 2 = 0. VoD = 1.8 V T Rpỷ 500 2 HEMA 1 V NEW, MW.10 L 0.18 Figure 6.42

Answer 1

You can find the solution below.What you did is absolutely right.I added some information.If you have any doubts ask me in the comment section below.If you like please upvote:)

Jo = funcox (2) (Vas-vres) Givey circuit Voo=1.8V Ro Sool VO uncox = VTH+ 0.4 5. Poonal + 그 LS 0.18 VAS-1-0 TT - We henow Fon linear/ miode VoscV95-VHS Jo = uncoxu (CVGS-vies) vos - Vos FO7, sarurafiour VOS Z VGS-14 A let's assume given mi in saturation 100 Tos Ź 200810 960) (-0.4) .! Jo = quna 270= VDO - VO 500 CS Scanned with CamScanner

VD - VDO ID 500 = 1.8 - Quni 500 = 1.8-2. Vo = 0.8 . NDSZ VGS-8th 08 706 Hence MOSFET iis satimation por Mieniomeen value of voo Mi mult mot Ecseen the triode regious VAS 3 VGs-vter [P if we put' siger MOSFET JUST Estet) Frau RVL along Pesło the saturation froin Triode] Coopo VOD - TORO ANOS cs Scanne: Vos E JORDFV0o-- CamScanners

Froon 04 - IDROT Voo = VGS-VH JORD+vgsöver =voa .: yoo = 2*10 € 500-10.4 Voo 1-1 70-4 - VDO KO.4V :! Voo 10:4V [voo 20-47 CS Scanned with CamScanner