Question

John is rollerblading down a long, straight path. At time zero, there is a mailbox about 1 m in front of him. In the 5 s time period that follows, John's velocity is given by the velocity versus time graph in the figure. Taking the mailbox to mark the zero location, with positions beyond the mailbox as positive, plot his position versus time in the given position versus time graph. Time (s) Position (m) Velocity (m/s) 0.0 1.0 3.0 4.0 5.0 2.0 Time (s) Assuming that all the numbers given are exact, what is John's position at a time of 4.73 s? Enter your answer to at least three significant digits. position at 4.73 s:

Answer 1

V t - 2 x l= -2 m m * 3 = Vt at to - t=} L= -- 2 = -3 m = -3+0 = -3 m X -3 -f = 3m 3 ts) interv (2-) Spead in 4.3 at 3 x C4.73-2) 2.46 m

S is displacement , which is equal to (v × t) for constant velocity (v).