Question

The figure shows a spherical shell with uniform volume charge density p-2.18 nC/m, inner radius a = 11.1 cm, and outer radius b = 2.7a. The inner hollow spherical volume does not carry any charge.

What is the magnitude of the electric field at radial distances (1) r = b, and (2) r = 3.00b, and explain why. (Use Gauss' Law definition)

Please show all work.

Answer 1

Fora Srb,consi der the spherical gaussioan surface with radius r inside the shellas shown in the figure The chages are uniformly distributed between the radius of the spherical shell of a SrSb The expression of volume charge density ρ is the ratio of the enclosed charges Qeid to the volume of the spherical shell and it can be expressed as follows nside The expression for volume of the spherical shell between the gaussian surface of radius r and the racdus a is, 4 en The expression for gauss lawis B(42) The equation (1) becomes as follows 36 b,then, from the above equation 1 Ifr (2 18 10 c)(27a 3(885x10 CIN m) (27a) (2.7a) -a* - 23.3N/C (2) Ifr-3b, then, from the above equation (3(2.7a) -a 3(2.7a 2.18x109 C 3(8.85x10-n C2 / N m 2) ( )2 - 73.6N/C s 74NIC