3. Convert the NFA of figure 1 to a DFA. The start state is q0, the accepting set is F = {q3}, and “epsilon” means .
3. Convert the NFA of figure 1 to a DFA. The start state is q0, the...
Consider the NFA N with states labeled q1, q2 and q3, where q1 is the start state and q2 and q3 are the final (accepting) states. The transition function for N is δ(q1,a) = {q1}, δ(q1,b) = {q1,q2}, δ(q2,a) = {q3}, δ(q2,b)= ∅, δ(q3,a)= ∅, and δ(q3,b)= ∅. Let L be the language recognized by N i.e. L(N). a) Draw the state diagram for N. b) Describe in plain English what's in the language L. c) Via the construction NFA to...
4. (5 points) Conversion form NFA to equivalent DFA Convert the following NFA into an equivalent DFA by using the Powerset-Construction. Write the transition table and draw the final DFA. start — 9o
Using the procedure demonstrated in class and in the textbook, convert this NFA to a DFA Using the procedure demonstrated in class and in the textbook, convert this NFA to a DFA. a, b b,c 91 92 93 E, C b, a
5.[10 points] Convert the following NFA to equivalent DFA E 1 a a, b 5.[10 points] Convert the following NFA to equivalent DFA E 1 a a, b
1.Calculate a regular expression corresponding to the following DFA, available at the jflap.org website, by the method of solving a system of simultaneous equations in standard form. q0 is indicated as the initial state. 2.Convert your regular expression to an NFA using the procedure of Hopcroft and Ullman 3.Convert the NFA - to a DFA. go q1 q2
3. (20) Using the procedure demonstrated in class and in the textbook, convert this NFA to a DFA a, b b, c 91 q2 q3 E, C b, a
7. Consider the following NFA 2 a, 7 Assume we convert this NFA to an equivalent DFA (without removing unnecessary states) Consider the following statements P the start state of the DFA is {1,2, 3) Qthe DFA has 24 accept states. R when the DFA is in state 5) and reads an a, it switches to the state 1,2,3, 4,5) Which of the following are correct? (a) P is true, Q is true, R is false. (b) P is false,...
Using the procedure demonstrated in class and in the textbook, convert this NFA to a DFA. a, b b, c 91 92 E, C 93 b, a
1. Use the construction of Theorem 2.2 to convert the nfa in Figure 2.10 to a dfa. Can you see a simpler answer more directly?
Help with answering the question at the bottom. Example of Reading an NFA Q = {q0, q1, q2, q3, q4} F = {q2, q4} L(M) = {x | x is a binary number that has 2 consecutive 0's or 2 consecutive 1's} = (0|1)^* (00|11) (0|1)^* Trs(q0, 0) = {q0, q3} (q0)--0à(q3) also, loop on q0 on 0,1 Trs(q0, 1) = {q0, q1} --1à(q1) Trs(q1, 1) = {q2} (q1)--1à((q2)) Trs(q2, 0/1) = {q2} loop on q2 on 0,1 Trs(q3, 0}...