given
m1 = 2.6 kg
m2 = 3.8 kg
m3 = 3.3 kg
d1 = 0.27 m
d3 = 0.45 m
from the realtion
moment inertia of a particle I = md^2
total moment on inertia of the three particle system
I = m1d1^2+m2(0)^2+m3*d3^2
I = 2.6*0.27^2+3.3*0.45^2 = 0.189+0.668
I = 0.857 kg m^2
a-PHY 2053-801 - Summer20 - WOODS > Activities and Due Dates > Chapter 8 Homework Assignment...
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