Determine the maximum deflection (in inches) if the load is 16
kips. E = 29,000 ksi and I = 500 in4.
Homework Answers
I am attaching the answer below in JPG file,if you completely understand the answer and if my answer is correct then please like my answer and if you have any doubt then comment below i will try my best to answer your queries.
Add Answer to:
Determine the maximum deflection (in inches) if the load is 16
kips. E = 29,000 ksi...
10 kips Determine the rotation at B and10 Kips vertical deflection at A for the beam...
10 kips Determine the rotation at B and10 Kips vertical deflection at A for the beam shown below. Use E-29,000 ksi and I-200 in4. Consider that 1 A 一®.7 A: is not constant when finding M/EI OTT 21 12' .. D diagram. 6 6'
2. Determine the natural period of vibration of the structure shown. E 29,000 ksi for the...
2. Determine the natural period of vibration of the structure shown. E 29,000 ksi for the columns. W = 2000 kips Cst case in ho dRigid beam 10 (I oc) I 214.5 in4 12 ft I 214.5 in4 a
Use Method of Virtual Work. 1. The 10 ft long steel (E = 29,000 ksi) cantilever...
Use Method of Virtual Work.
1. The 10 ft long steel (E = 29,000 ksi) cantilever beam shown below has a fixed support at the left end (Point A). The beam supports a 10 kips (downward) load at Point B and a 50 k-ft "point couple" (clockwise) at the free end of the cantilever (Point C). Region AB is 6 ft long with moment of inertia IAB = 500 in". Region BC is 4 ft long with moment of inertia...
Curious on this question. For the steel bars (E = 29,000 ksi) and loading shown, determine...
Curious on this question.
For the steel bars (E = 29,000 ksi) and loading shown, determine the vertical displacement at point A. Assume that P = 46.4 kips and both areas have a cross section area A 1.5 in. Report your answer in inches to three decimal places and place your answer in the box below 2 ft 1.5 ft 15 ft
Problem #3 GIVEN: E = 29,000 ksi I = 1000 in4 OK 40K 15 33.3K 6.7K...
Problem #3 GIVEN: E = 29,000 ksi I = 1000 in4 OK 40K 15 33.3K 6.7K 30 FIND: Find the deflection at point D by virtual work. (Mm) Answer will be in inches, and give direction.
I= 940 in^4; E= 29050 ksi. Values for a= 9 and c= 7; please help!! Problem...
I= 940 in^4; E= 29050 ksi. Values for a= 9 and c= 7; please
help!!
Problem #1 The Moment of Inertia I = (900 + 5 b) in^ and Modulus of Elasticity E = (29,000 + 50 d) ksi. Determine the vertical deflection at point B on the beam. (Note: Provide your answer in units of inches using 3 significant digits of accuracy.) (1 + a) kips/ft C! A B |--(4+ c) ft- (10 + C) ft
Problem 4 Use the conjugate beam method to determine the slope and deflection at point B...
Problem 4 Use the conjugate beam method to determine the slope and deflection at point B of the beam shown. E- 29,000 ksi. I-3,000 in4. 2 k/ft 30 ft
A 8 kip load is applied at the center of a propped cantilever wood beam (E...
A 8 kip load is applied at the center of a propped cantilever wood beam (E 1,200 ksi, and I - 200 in4). If the span length of the beam is 11 ft, what is the centerline deflection, in inches, of the beam?
А w18 x 40 steel spandrel (edge) beam spans 20'. The beam supports a uniform floor live load of 1 kip/ft and a uniform floor dead load of 0.5 kip/ft. The beam also supports brick veneer weigh...
А w18 x 40 steel spandrel (edge) beam spans 20'. The beam supports a uniform floor live load of 1 kip/ft and a uniform floor dead load of 0.5 kip/ft. The beam also supports brick veneer weighing .6 kip/ft as a uniform dead load. The maximum allowable total load deflection for beams supporting masonry (brick or block) is L/640. Calculate the live load and total load deflections. Do the live load and total load deflections exceed the allowable deflections for...
16. Beam Deflection Using the method of progressive diagrams, find the centerline deflection for the given...
16. Beam Deflection Using the method of progressive diagrams, find the centerline deflection for the given beam. Give the required values for each diagram (load, shear, moment slope(EI) and deflection) shown in the problem statement (see the pdf). 3 w 1 DATASET: 1 -2. Length A Length B Point Load P Uniform Load w Modulus of Elasticity Moment of Inertia 9 FT 10 FT 13 KIPS 1 KLF 29000 KSI 600 IN 4 -A- B- -- A - Correct Answer...
10 kips Determine the rotation at B and10 Kips vertical deflection at A for the beam shown below. Use E-29,000 ksi and I-200 in4. Consider that 1 A 一®.7 A: is not constant when finding M/EI OTT 21 12' .. D diagram. 6 6'
2. Determine the natural period of vibration of the structure shown. E 29,000 ksi for the columns. W = 2000 kips Cst case in ho dRigid beam 10 (I oc) I 214.5 in4 12 ft I 214.5 in4 a
Use Method of Virtual Work.
1. The 10 ft long steel (E = 29,000 ksi) cantilever beam shown below has a fixed support at the left end (Point A). The beam supports a 10 kips (downward) load at Point B and a 50 k-ft "point couple" (clockwise) at the free end of the cantilever (Point C). Region AB is 6 ft long with moment of inertia IAB = 500 in". Region BC is 4 ft long with moment of inertia...
Curious on this question.
For the steel bars (E = 29,000 ksi) and loading shown, determine the vertical displacement at point A. Assume that P = 46.4 kips and both areas have a cross section area A 1.5 in. Report your answer in inches to three decimal places and place your answer in the box below 2 ft 1.5 ft 15 ft
Problem #3 GIVEN: E = 29,000 ksi I = 1000 in4 OK 40K 15 33.3K 6.7K 30 FIND: Find the deflection at point D by virtual work. (Mm) Answer will be in inches, and give direction.
I= 940 in^4; E= 29050 ksi. Values for a= 9 and c= 7; please
help!!
Problem #1 The Moment of Inertia I = (900 + 5 b) in^ and Modulus of Elasticity E = (29,000 + 50 d) ksi. Determine the vertical deflection at point B on the beam. (Note: Provide your answer in units of inches using 3 significant digits of accuracy.) (1 + a) kips/ft C! A B |--(4+ c) ft- (10 + C) ft
Problem 4 Use the conjugate beam method to determine the slope and deflection at point B of the beam shown. E- 29,000 ksi. I-3,000 in4. 2 k/ft 30 ft
A 8 kip load is applied at the center of a propped cantilever wood beam (E 1,200 ksi, and I - 200 in4). If the span length of the beam is 11 ft, what is the centerline deflection, in inches, of the beam?
А w18 x 40 steel spandrel (edge) beam spans 20'. The beam supports a uniform floor live load of 1 kip/ft and a uniform floor dead load of 0.5 kip/ft. The beam also supports brick veneer weighing .6 kip/ft as a uniform dead load. The maximum allowable total load deflection for beams supporting masonry (brick or block) is L/640. Calculate the live load and total load deflections. Do the live load and total load deflections exceed the allowable deflections for...
16. Beam Deflection Using the method of progressive diagrams, find the centerline deflection for the given beam. Give the required values for each diagram (load, shear, moment slope(EI) and deflection) shown in the problem statement (see the pdf). 3 w 1 DATASET: 1 -2. Length A Length B Point Load P Uniform Load w Modulus of Elasticity Moment of Inertia 9 FT 10 FT 13 KIPS 1 KLF 29000 KSI 600 IN 4 -A- B- -- A - Correct Answer...
Most questions answered within 3 hours.
-
Koch Realty has owned a vacant land with a FMV of
$775,000 and an adjusted basis...
asked 1 minute ago -
It is estimated 29% of all adults in United States invest in
stocks and that 85%...
asked 1 minute ago -
What does a 2-sided p value of 0.04 mean? (I am not asking if it
is...
asked 15 minutes ago -
A parallel-plate capacitor is made from two aluminum-foil
sheets, each 7.8 cmcm wide and 5.1 mmlong....
asked 16 minutes ago -
1. why is toluene a stronger nucleophile than benzene?
2.why is phenol a stronger nucleophile than...
asked 33 minutes ago -
4. How can you solve for the density of the liquid from the
slope? Please show...
asked 33 minutes ago -
when 2053 j of heat is added to 46.3 g of hexane C6H14 the
temperature increases...
asked 56 minutes ago -
I need new and unique answers, please. (Use your own words,
don't copy and paste), Please...
asked 59 minutes ago -
MCL 445.111 et seq. deals with Home Solicitation Sales.
MCL stands for Michigan Compiled Laws which...
asked 50 minutes ago -
Which of the following items may not create an NOL?
a.
sole proprietorship loss
b.
personal...
asked 55 minutes ago -
A hypothetical solution forms between a solid and a liquid. The
values of the thermodynamic quantities...
asked 53 minutes ago -
a)An ideal heat pump is being considered for use in heating an
environment with a temperature...
asked 56 minutes ago