Question

Chrome File Edit View History Bookmarks People Tab Window H Analogy x G Suppose x Quiz: Mid x G how to so X + → ☆ O M C templeu.instructure.com/courses/73442/quizz... What's printed when we run the following code? class Stuff { int x; public Stuff(int newx) { X = newX; . public class WhatsPrinted { public static void more (Stuff s S.X++; { public static void main(String [args) { Stuff sl = new Stuff(10); Stuff s2 = sl; if (sl =2) { System.out.println("same"); } else { System.out.println("different"); same different

Answer 1

Answer

The answer will be "same" because we create a Stuff object s1 and it has it attributes x value as 10 assigned to it. Now, we create another Stuff object s2 and we do Stuff s2 = s1. This line basically make s2 instance to point to s1 object only. So, both s1 and s2 are pointing to the same Stuff object.

I hope this will make things clear. If any doubt do comment and do upvote if you like my answer.