Question

In a recent Super Bowl, a TV network predicted that 93 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 57 people who saw the commercials and found that 50 of them said they would watch one of the television shows. Suppose you are have the following null and alternative hypotheses for a test you are running: H 0 : p = 0.93 H0:p=0.93 H a : p > 0.93 Ha:p>0.93 Calculate the test statistic, rounded to 3 decimal places z =

Answer 1

42 H. hWe knew thhat 50 -0.93. Test staiabu Undlu Mo 093x0.07 yoret H.aud mot quala thon 093