Question

In the circuit in the figure below, the batteries have negligible internal resistance. (Take R1=2.95 Ω, R2=3.80 Ω,  and  R3=6.80 Ω ).

(a) Find the magnitude of the current in each resistor.

(b) Find the magnitude of the potential difference between points a and b.

(c) Find the power supplied by each battery.

In the circuit in the figure below, the batteries have negligible internal resistance. (Take R1 2.95 , R2 3.80 2, and R3 -6.80 2.) 120VT Rs 12.0V (a) Find the magnitude of the current in each resistor. 12.95Ω 13.80Ω = 16.30Ω = b) Find the magnitude of the potential difference between points a and b. (c) Find the power supplied by each battery left battery right battery


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Answer #1

a] Let the current be i1, i2 , i3

By kirchoffs node rule, i1+i2 -i3 =0

12 - R1i1 - R3i3 = 0 or 12 -2.95i1- 6.80i3 =0

12 - R2i2 - R3i3 = 0 or 12 -3.80i2- 6.80i3 =0

solving the three equations,

i1 = 0.80 A, i2 = 0.62A, i3 = 1.42A

b]Vab = i3R3 = 1.42*6.80 = 9.65 V

c] Left battery = i2*V2 = 0.62*12 = 7.44 W

right battery = i1V1 = 0.80*12 = 9.6 W

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