In the circuit in the figure below, the batteries have negligible internal resistance. (Take R1=2.95 Ω, R2=3.80 Ω, and R3=6.80 Ω ).
(a) Find the magnitude of the current in each resistor.
(b) Find the magnitude of the potential difference between points a and b.
(c) Find the power supplied by each battery.
a] Let the current be i1, i2 , i3
By kirchoffs node rule, i1+i2 -i3 =0
12 - R1i1 - R3i3 = 0 or 12 -2.95i1- 6.80i3 =0
12 - R2i2 - R3i3 = 0 or 12 -3.80i2- 6.80i3 =0
solving the three equations,
i1 = 0.80 A, i2 = 0.62A, i3 = 1.42A
b]Vab = i3R3 = 1.42*6.80 = 9.65 V
c] Left battery = i2*V2 = 0.62*12 = 7.44 W
right battery = i1V1 = 0.80*12 = 9.6 W
In the circuit in the figure below, the batteries have negligible internal resistance.
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