Problem 2.058 SI The net work of a power cycle operating as in the figure below...

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Problem 2.058 SI The net work of a power cycle operating as in the figure below is 5.000,000 kJ, and the thermal efficiency is 0.5 Hot body SystemH out Cold body Determine the heat transfers Qin and Qout, each in kJ. Qin = Qout = Click if you would like to Show Work for this question: k) k) Open Show Work

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Answer 1

Answer #1

Wcycle = Qin - Qout

Wcycle = 5 KJ ( if 5.000,000 KJ = 5 KJ )

$\eta$ = 0.5 ( thermal efficiency )

$\eta$ = Wcycle / Qin

0.5 = 5 KJ / Qin

Qin = 10 KJ

Qout = 5 KJ

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Answer 2

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