Question

According to the following reaction, how many grams of copper are required for the complete reaction of 21.5 grams of silver nitrate? silver nitrate(aq) + copper(s)-copper(II) nitrate(aq) + silver(s) grams copper

Answer 1

Ans :

The balanced equation is given as :

2AgNO3 (aq) + Cu (s) = Cu(NO3)2 (aq) + 2Ag (s)

Number of mol of silver nitrate = mass / molar mass

= 21.5 g / 169.87 g/mol = 0.126 mol

So number of mol of copper required = 0.126 mol / 2 = 0.063 mol

Mass of copper = mol x molar mass

= 0.063 mol x 63.546 g/mol

= 4.02 grams copper