A BMX cyclist rides off a 2.50m high ramp with an initial velocity of 18.0 m/s at an angle of 40.0 degrees above horizontal. Find the time it takes for the cyclist to land on the gound and the distance from the base of the ramp to the landing point.
from the kinematic equation
y = usintheta*t-1/2gt^2
4.9 t^2-18sin40*t-2.5 = 0
4.9t^2-11.57t-2.5 = 0
roots are
t =2.56 and -0.199 s
so answer is t = 2.56 s
A BMX cyclist rides off a 2.50m high ramp with an initial velocity of 18.0 m/s...
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