13/14)
Mass of sucrose 200gm
Molar mass of sucrose 342 gm /mol
Moles of sucrose =mass taken/molar mass=200/342=0.58
Mass of water taken 350gm
Molar mass of water 18gm
Moles of water =mass taken/molar mass= 350gm/18gm=19.44
Mole fraction of water = moles of water/(moles of water +moles of sucrose) =19.44/(19.44+0.58)=19.44/20.02=0.971
According to the Raoults law
Vapour pressure of solution =mole fraction of water&vapour pressure of pure water =0.971*17.5 mm of Hg=16.99 mm of Hg (nearly 17 mm of Hg) option 3 is correct
15/16
Moles of sucrose 0.31
Mass of water 175g =0.175 kg (1kg =1000g)
Molality =moles of sucrose/ mass of water= 0.31moles/0.175kg=1.77 m
Depression in freezing point is given by
So
=3.30C
So freezing point of solution =freezing point of pure water -depression in freezing point=(0-3.3)0C=-3.30C
option a is correct
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