Question

The drawing shows the electric potential as a function of distance along the x axis. Determine the magnitude of the electric field in the region (a) A to B. (b) Blo , and (c) 'o V. Potential, V 0 0.20 0.60 0.80 0.40 X, m (a) Number Units (b) Number Units . (c) Number Units

Answer 1

Solution ca) potential at A is Vp = 5.00 Potential at B is V2 = 5.00 Position at A is n, om Position at Bis x₂ = 0.20m We know that the relation between the electric field and potential difference is Tesorero E:- CVR-n) 2 HI 0. 20-6 lbl - 2.0 F:-(5-5). [E = 0.0 Ne Top 10 = 0.0 V/m Potential at B is V8 5.00 Potential at c is ve: 3.00 Position at Bis 2 = 0.20m Position at c is H₂ = 0.40m from equation ! c ov - - (V - VB .130 [:-X TE: 10.0 Vienn] potential at cin ve 3.0V, Position at & is = 0.40m Potential at Dis Volov, Position at & is tui 0.80m from equation on AV = -(V-vel = -(1.0-3.0) - 2.0 [E = 50 V/m) X 0. 2 -X 0.4 (c) 1 My-X3 0.8 -0.07 E = 5.6