Question

leted helow are systolic blood pressure measurements (mm Hg) taken from the rieht and le arms of the same woman. Assume that the paired sample data is a simple random sample and that une aas have a distribution that is approximately normal. Use a 0,05 significance level to test the claim that is a difference between the measurements from the two arms. (14 points) 136 Right arm Left arm 151 144 129 135 168 180 174 140 145 -32 -29 Differences: -30 -11 -10 1. Extract Information: (Round to three decimal places) (2 points) 2. Original Claim: (1 point) 3. Identify the null and alternate hypothesis. (2 points) 4. Test Statistic: (Use formula) (Round to three decimal places) (2 points) 5. Distribution (Graphically): (1 point) 6. P-value: (Show all your work how to find P-value) (Round to four decimal places) (2 points) 7. Statistical Conclusion: (2 points) claim that difference 8. Final Words: (2 points) sufficient evidence to There between the measurements from the two arms.

Answer 1

EX-ADS) Given that: xo Right Arm of I X2 Left Arm. qe difference = 24-72 veing Ercel for calculations! PE =' - 22:47 Sd - 18cq-)2 - 10.992 V not SGV 9H 10 Claim • There is difference beliceen measurements Imobius from the too arms P2.00 To lost hypothesis of un d Horeld oot ng ng wadon gilt noord H1:480

DATE 46 Test Statistice. 9119 trol de - 22.4 -4.586 10.922 A NCOULD Rejection -tding O - ta/2 Acceptance & Region Rejection 6 p-value = 29[Tn-117 Itcal T I = 21 [ Ty 7, 84 5867 - from t-table [p-value = 0.01011 Here P-value Ld=0.05 of we reject Ho at d = o.or 8 3 0 0 .00 conclusion &. There is sufficient evidence to rejeet 4o at d 0.05. if may be condude that there is difference between the measurements from the two alems.