10-4. Consider the diprotic acid H A with Ki = 1.00 X 10" and K =...

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Question

10-4. Consider the diprotic acid H A with Ki = 1.00 X 10 and K = 1.00 X 10 8. Find the pH and concentrations of H2A, HA, an

Answer 1

Answer #1

The dissociation of diprotic acid is given by HA 0.100 Initial Change Equilibrium 0.100-X ✓ [H+][HA] _ x.x_=1.00x104 sa [H,A]

HA- will further dissociates into Hi and A-2 Let y be the change in the conc. of all species at equilibrium. H+ HA A 0.003113

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(b) (b) 0.100 M of NaHA solution. This is intermediate form. So for this [HA-] = [NaHA] = 0.100 M Conc. of H+ is calculated as H+

N 20[*00ʻI -01 x00I=- 0010* -0[*00-1 =-] [-H] I-VH]*3-0[*00-1-1-28] [YH] = 1.00 x 10-8 W-01 ~ 00ʻI= +01X00ʻI -01*00T (0010)

Answer 2

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