Question

In need of help to find the Kinetic energy lost, also need to make sure that im doing the chart correctly please. the formula to fine the kinetic energy lost is below

thank you!

Procedure B. m; % difference mass of blue PasCar 0.254 KA (blue) (real m L M v. (kg) (kg) (kg) (m/s) 10.254 0.754 1.008 0.31 10.254 10.504 0.758 10.35 0.254 10.254 0.509 0.49 10.504 0.254 0.758 10.94 10.754 0.254 1.008 0.42 10.504 0. 04 1.008 0.18 mo = Muf V pred. v (m/s) (m/s) 0.04 10.08 0.06 0.12 10.14 10.25 0.48 0.63 0. 31 0.31 0.08 0.09 50.0%. 44.0%. 23,8%. 0.07. 11.1% [/m, ro27 1₂ M ve 2] A. K Kiost KK M (kg) (kg) 60.254 1.008 0.254 0.758 ③ 0.54 0.508 6o. 504 0.750 6 0.754 1.008 O o.soy 1.008 V ko - (0.254) (0.312 ko=0.012 = 1/2 (0.254) (0.352 ko=0.016 0.012 0.0008 0.016 To.0014 1 0.031 0.0049 0.223 10.0873 0.067 0.0484 0.008 0.0032 0 kf = 1/(1.008) (0.04) 2008,064% 10 - 6 - 10 Kf = Y(0.758)(0.06)2 0.0014

Answer 1

Ко (3) oo 12 Klost/ko б:33 б.91 3 О. Ф1 С. О-ОЗІ б. 2 23 ODG? K, C3) обь8 O, Do) ч. обоча б. 6Q-3 б: о Ч8 ч. o, Oo 32 Kiou (tyko) О. b12 бо че б 0 261 о. ) 35С. бо 13 60048 (б: 892 бGo8 De8 ос 6. ОС9