Question

Python: using a stack, implement a function that takes in an arithmetic expression, and evaluates it,...

Python: using a stack, implement a function that takes in an arithmetic expression, and evaluates it, supported operations are + and -, which have same precedence.

Note: one way to do it is to scan the entire expr pushing numbers onto val-stack and operations on op-stack until tokens in expr are done. Then, use a loop to pop two numbers from val-stack and one operation from op-stack, evaluate, and push results back to val-stack, until op-stack is empty.

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Answer #1

#source code:

a=input("Enter Expression:")
val_stack=[]
op_stack=[]
for i in range(len(a)-1,-1,-1):
   if(a[i]=="+" or a[i]=="-"):
       op_stack.append(a[i])
   else:
       val_stack.append(float(a[i]))
while(len(op_stack)!=0):
   a=val_stack.pop()
   b=val_stack.pop()
   op=op_stack.pop()
   if(op=="+"):
       val_stack.append(a+b)
   elif(op=="-"):
       val_stack.append(a-b)
print("The output of Expression is:",val_stack[0])

a-input (Enter Expression: ) val_stack-[] op_stack- for i in range (len (a) -1,-1,-1) a [i- ) op_stack.append (a [i] ) if

#output:

C:\Users\vishnu\Desktop>python r.py Enter Expression:2+3 The output of Expression is: 5.0 C:\Users\vishnu\Desktop>python r.py

#if you have any doubts comment below...

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