Tension in the cable is given by
T = m( g + a)
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a) T = 2000*(9.8+ 1.5) = 22600 N
b) T = 2000 (9.8 - 1.5) = 16600 N
c) T = 2000 (9.8 +0) = 19600 N
d) T = 2000 (9.8 +0) = 19600 N
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6.
Acceleration of this Atwoods machine is given by
a= g ( m1 - m2) /(m1 + m2)
a = 9.8 ( 3.55 - 2.77)(3.5 + 2.77) = 1.21 m/s^2
Tension is given by
T = 2.77 ( 9.8 + 1.21) = 30.5 N
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Comment in case any doubt.. Goodluck
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