Looking at the big O of functions,
If f1(N)=O(NlogN) and f2(N)=O(log N), then what is "big O" of f1 +f2?
From the question:
f1(N)=O(NlogN)
Here the function grows logarithemically as well as sequentially.
f2(N)=O(log N)
Here the function grows only logarithemically.
f1+f2 is the sun of O(NlogN) + O(log N).
In the above O(NlogN) > O(logN)
So we can justify that f1 has highest complexity.
In Big O addition calculation highest complexity is the overall complexity.
The overall complexity is O(NlogN).
Therefore f1 +f2 = O(NlogN).
Looking at the big O of functions, If f1(N)=O(NlogN) and f2(N)=O(log N), then what is "big...
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