Question

C programming

3. (40 pts) Define an array fof size 10, using call-by-reference (that is, use of pointers), to pass the array to a function, named summation In main: define array, pass array, print out the array and the results on screen In function summation: take array from main and sum the array using the formula below: 10 fO 2 246 NOTE: you must use call-by-reference (the pointer) to call functions, as required; otherwise, no credits will be given.

Answer 1

#include<stdio.h>
#include<stdlib.h>
//defination of summation()
double summation(int *f)
{
    int i;
    double sum=0;
    for(i=0;i<10;i++)
    { //find the sum by multiplying the element by 3
        if(i%2==0)
        sum= sum + *(f+i) * 3;
        else
        //find the sum by multiplying the element by 2
        sum = sum + *(f+i) * 2;
   }
   //multiply by 1/2
   sum = 0.5 * sum;
   //return the sum
   return sum;
}
int main()
{
    int *f,i;
    double sum;
    //allocate 10 memory cells for the array dynamically
    f= (int *)malloc(10 * sizeof(int));
    //loop to input the array elements
    for(i=0;i<10;i++)
    {
        printf("\n Enter a number");
        scanf("%d",f+i);
   }
   //display the array elements
   printf("\n The array elements are \n");
   for(i=0;i<10;i++)
   printf(" %d ",*(f+i));
   //call to the summation() method by call by reference
   sum=summation(f);
   //display the sum according to the formula given
   printf("\n Sum of the array elements according to the formula is %5.2lf",sum);
}

OUTPUT

CAUserstROZYnKRISHNADesktopisum.exe Enter a number2 Enter a number3 Enter a number 5 Enter a number6 Enter a number8 Enter a number12 Enter a number1 Enter a number4 Enter a number3 Enter a number 5 The array elements are 2 3 5 6 8 12 10 4 3 5 Sum of the aray elements according to the formula is 72.00 Process exited after 16.54 seconds with return ualue 61 Press any key to continue .. .

note : in question the formula is not clearly visible . I have multiply 3 and 2 . If that symbol is not '*' so just change the statement sum= sum + *(a+i) * 3; to sum= sum + *(a+i) + 3; and sum= sum + *(a+i) * 2; to sum= sum + *(a+i) + 3;