![A diamagnetic atom or ion has no unpaired electrons in any of its orbitals, whereas a paramagnetic atom or ion has at least one unpaired electron in its orbitals. The more unpaired electrons, the more paramagnetic the atom or ion. What is the ground-state electron configuration for the V3 ion and is it paramagnetic or diamagnetic? [Ar] 4s 3d05s diamagnetic O [Kr] 5s, paramagnetic [Ar]4s 3d, paramagnetic [Ar] 4s, diamagnetic [Ar] 3d, paramagnetic](http://img.homeworklib.com/questions/7f24edf0-288a-11eb-a643-895a81e9c0f9.png?x-oss-process=image/resize,w_560)
Homework Answers
The ground state electronic configuration of Vanadium is Ar [4s2] [ 3d3] So, losing three electrons from its outermost shells, the configuration V3+ is Ar [4s0] [ 3d2] which is same as Ar [3d2]. Now, in the 3d orbital there are 2 unpaired electrons. Therefore the V3+ ion is paramagnetic.
The answer is the last option.
d orbital filling:
maximum electrons capacity = 10
Each gets filled with one electron each and then from the 6th electron they get paired.
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