0 14 + x2 2. (3 points) Solve the initial value problem xy'–3y = x?, y(i)=
38. Solve the initial value problem x+3y=+*2 + 2xy +T Y() = -2 2xy x2 + 2x2y + 1 Ti y(1) = -2.
Solve the initial value problem. y'" – 3y" - y' + 3y = 0; y(0)=5, y'0) = -3. y'(0)=5 The solution is y(t) =
[10] 2. Solve the initial value problem (x² + 3y² + x)y' + 2xy + y = 0, y(1) = 1.
Problem 1: Solve the initial value problems: a 2y" – 3y' +y=0 y(0) = 2, 7(0) = 1 by' + y - 6y = 0 y(0) = -1, y'(0) = 2 cy' + 4y + 3y = 0 y(0) = 1, y'(0) = 0 Problem 2: Solve the initial value problems: a y' +9y = 0 y(0) = 1. 1'(0) = -1 by" - 4y + 13y = 0 y(0) = 1, y'(0) = 3 cy" + ly + ly...
#6 Solve the initial value problem y(0)- 2, y,(0) 1 y"-3y' + 2y-6(t-3);
15. (8 points) Solve the initial value problem y" + 4y' + 3y-хез®, y(0) 1, y'(0) 0
[10] 2. Solve the initial value problem (x^ + 3y^ + c)2 + 2xy + y = 0, g(1) = 1.
Solve the initial value problem y" + 3y' + 2y = 8(t – 3), y(0) = 2, y'(0) = -2. Answer: y = u3(t) e-(-3) - u3(t)e-2(1-3) + 2e-, y(t) ={ 2e-, t<3, -e-24+6 +2e-l, t>3. 5. [18pt] b) Solve the initial value problem y' (t) = cost + Laplace transforms. +5° 867). cos (t – 7)ds, y(0) – 1 by means of Answer:
Solve the initial value problem y" – 3y' + 2y = e3r, y(0) = 2, y'(0) = -1. (a) y(x) = 40-1 – 4e2+ 2e 32 (b) y(x) = 1 e?' – 4e-2x + £230 (c) y(x) = 40-1 – 4e-2x + 3e3x (d) y(x) = 40" – 4e2x + e3r Select one: a с b d