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10) The velocity (t) of a particle as a function of time is given by (h) - 023 m/s) (4.1 m/s2)+- (62 m/s3)2. What is the aver
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Answer #1

10) A) 15 m/s^2

given

v(t) = 2.3 + 4.1 t - 6.2 t^2

at time t1 = 1 s,

v1 = 2.3 + 4.1*1 - 6.2*1^2

= 0.2 m/s

at time t = 2 s

v2 = 2.3 + 4.1*2 - 6.2*2^2

= -14.3 m/s^2

average acceleration between t = 1 s to t = 2s

a_avg = (v2 - v1)/(t2 - t1)

= (-14.3 - 0.2)/(2 - 1)

= -14.5 m/s^2

= -15 m/s^2 (when rounded to two significant figures)

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