10) A) 15 m/s^2
given
v(t) = 2.3 + 4.1 t - 6.2 t^2
at time t1 = 1 s,
v1 = 2.3 + 4.1*1 - 6.2*1^2
= 0.2 m/s
at time t = 2 s
v2 = 2.3 + 4.1*2 - 6.2*2^2
= -14.3 m/s^2
average acceleration between t = 1 s to t = 2s
a_avg = (v2 - v1)/(t2 - t1)
= (-14.3 - 0.2)/(2 - 1)
= -14.5 m/s^2
= -15 m/s^2 (when rounded to two significant figures)
10) The velocity (t) of a particle as a function of time is given by (h)...
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