An enzyme catalyzes a reaction with a Km of 9.50 and a Vmax of 1.75
An enzyme catalyzes a reaction with a Km of 9.50 and a Vmax of 1.75 An...
An enzyme catalyzes a reaction with a Km of 5.00 mM and a Vmax of 1.85 mM s-1. Calculate the reaction velocity, vo. for the following substrate concentrations. a) 3.00 mM Number mM.s b) 5.00 mM Number mM.s c) 10.5 mM Number
An enzyme catalyzes a reaction with a Km of 9.00 mM and a Vmax of 3.95 mM·s–1. Calculate the reaction velocity, v0, for the following substrate concentrations: A. 1 mM B. 9 mM C. 11 mM
An enzyme catalyzes a reaction with a Km of 8.00 mM and a Vmax of 4.45 mM s-1. Calculate the reaction velocity, Vo, for the following substrate concentrations a) 1.00 mM Number mM.s-1 b) 8.00 mM Number mM s-1 c) 11.0 mM Number mM.s-1
An enzyme catalyzes a reaction with a K of 6.50 mM and a Vmax of 2.75 mM s velocity, vo. for the following substrate concentrations a) 2.50 mM Calculate the reaction Number mM. sl b) 6.50 mM Number c) 14.0 mM Number mM.sl
An enzyme catalyzes a reaction with a Km of 8.50 mM and a Vmax of 2.70 mM 5-1. Calculate the reaction velocity, vo, for each substrate concentration. [S] = 2.25 mM Vo: 0.5 mM.s-1 [S] = 8.50 mM 1.70 mMs-1 [S] = 13.0 mM [S] = 13.0 mM Vo: 2.05 mm. s-1
Score: 3318/3/00 15 of 37 > An enzyme catalyzes a reaction with a km of 8.50 mM and a Vmax of 2.45 mM.s. Calculate the reaction velocity, to, for each substrate concentration. S = 3.75 mm mMs-1 S = 8.50 mM mM.s-1 [S] = 10.5 mM about us Careers Privacy policy terms of use contact us help
An enzyme catalyzes the reaction M↽−−⇀N . An enzyme catalyzes the reaction M = N. The enzyme is present at a concentration of 3.5 nM, and the Vmax is 1.9 uM -. The Km for substrate M is 2.9 uM. Calculate kcat kcat = 542.86 What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 1.5? apparent Vmax = 0.526 UM s-1 apparent Km = 1.2
An enzyme catalyzes the reaction M N. The enzyme is present at a concentration of 3.5 nM, and the Vmax is 2.9 PM s-. The Km for substrate M is 6.5 MM. Calculate kcat kcat = 1 What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 1.3? apparent Vmax = UM S-1 apparent Km = UM
10. An enzyme catalyzes the reaction of Y to Z. The enzyme is present at a concentration of 1 nM. and the Vmax is 2 M/s. The Km for substrate Y is 4 M. Calculate kot
Biochemistry Chapter 6 : Vmax and Km Estimation of and V_max and K_m by Inspection Although graphical methods are available for accurate determination of the V_max and K_m of an enzyme-catalyzed reaction (see Box 6-1), sometimes these quantities can be quickly estimated by inspecting values of V_0 at increasing [S]. Estimate the V_max and K_m of the enzyme-catalyzed reaction for which the following data were obtained.