The critical region for 95% confidence interval is
if z <= -1.96 or z >= 1.96, reject H0
Since test statistics zc is greater than 1.96, that is test statistics lies in rejection region, so we reject the null hypothesis.
19. Given a test statistic: Zc 2 and the known Z-values for common confidence intervals: 1.645,...
Match the critical value with the confidence level. 2.576 1.96 1.645 2.326 1. 90% 2. 95% 3. 98% 4. 99%
Find the margin of error for the given values of c, o, and n. c = 0.90, c = 3,4, n= 100 Click the icon to view a table of common critical values. E (Round to three decimal places as needed.) i Table of Common Critical Values Zc Level of Confidence 90% 95% 99% 1.645 1.96 2.575 Print Done
In a difference of proportion test with alpha = .05, the critical values(s) for a two-tailed test is/are -2.575 and 2.575 1.96 -1.645 and 1.645 -1.96 and 1.96 If the test statistic for a difference of means test has a p-value of .065, we could reject the Null Hypothesis at an alpha level of.10. True False
Read the z statistic from the normal distribution table and circle the correct answer. A one-tailed test (upper tail) at a 123 level of significance, a. 1.645 b. 1.54 C. 1.96 O d. 1.16 When the hypotheses Ho μ z 100 and Ha μ < 100 are being tested at a level of significance of o, the null hypothesis will be rejected if the test statistic z is a. -za O c. 100 For a one-tailed test (upper tail) with...
Given the following null and alternative hypotheses, the test statistic from the sample data is z=1.875z=1.875. If the significance level of 0.05 which results in a critical value of 1.645, what is the conclusion as it relates to the null hypothesis? H0:p=0.22 H1:p>0.22 Fail to reject the alternative hypothesis Reject the null hypothesis Fail to reject the null hypothesis Support the null hypothesis
Out of 500 people sampled, 450 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Do not use StatCrunch. Show all formulas used, work and steps. Be sure to define your variables. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 1.96 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval Give your answer in...
Answers only is fine! Find the critical value zc necessary to form a confidence interval at the level of confidence shown below. c=0.92 Find the margin of error for the given values of c, σ, and n. c = 0.95, σ =2.4, n = 8.1 Level of Confidence. zc 90% 1.645 95% 1.96 99% 2.575 Construct the confidence interval for the population mean μ. c=0.98, x=9.5, σ=0.3, and n= 52 Construct the confidence interval for the population mean μ. c=0.95, x=16.7, σ=6.0, and n=...
For the following sample sizes and confidence levels, find the t-values suitable for building confidence intervals: a) n = 15; 90%. b) n = 6; 95%. c) n = 19; 99%. d) n = 25; 98%. e) n = 10; 99%. f) n = 41; 90%.
CHALLENGE ACTIVITY 5.3.1: Confidence intervals for population proportions. Critical values for quick reference during this activity. Confidence level Critical value 0.90 = 1.645 0.95 z* = 1.960 0.99 2.576 Jump to level 1 In a poll of 1000 randomly selected voters in a local election, 34 voters were against fire department bond measures. What is the 99% confidence interval? (Ex: 0.123 Ex: 0.1230 ] (smaller value, larger value] 2 Check Next Feedback
cal values for quick reference during this activity. Confidence level Critical value 0.90 z* = 1.645 0.95 1.960 0.99 2.576 Jump to level 1 1 A poll reported 65% support for a statewide election with a margin of error of 4.33 percentage points. 2 How many voters should be sampled for a 95% confidence interval? Round up to the nearest whole number 4 Ex: 1234 voters 3 Check Next Feedback?