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The system is released from rest while in the position shown. If m1 = 0.84 kg, m2 = 3.03 kg, d = 0.52 m, and 0 = 19°, determi

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(mit a m,=.84 kg m2=3.03 kg d=.52m o= 10 acceleration to me = b (wor.t ground) acceleration of m, = a. (w.y.t wedge) FBD of wFBO of block LAN maz here ma is posendo force. mig caso = N + mar sino mg sind + marcoso = ma, PW N= M₂Qz/sino mg caso & Ma2Vaiz? - U. z = 2 ad Vis - 2 x 3.963 x .52 V₂ = 2.03 min t = vil = 5122 sec. vz = A xt w = .4166 mis ) Ni V = (Vizcos 19 - ₂)²

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