Question

using c++ program the following

The Assignment For this assignment, we are asking you to implement Conway's Game of Life using a two-dimensional array as a grid in which to store the cells. Live cells are denoted as * characters, dead cells are denoted by the character. Input As input, you will be given a line containing the number of rows, number of columns, and number of generations to simulate in the form mng followed by m lines containing the initial state of the grid. 3 <= m,n <= 20 and @ <= g <= 50 For example, a 4 x 5 grid on which 7 generations of life should be simulated, would be given as follows: 4 5 7 . You should store this initial grid state in a multidimensional array as discussed in class. Your Task The initial state (generation 0) stored in a grid. Innneration 11 by applying the rules to the previous generation grid

Answer 1

#include <iostream>

#include <ctime>

#include <cstdlib>

using namespace std;

int main() {

srand(time(NULL)); // GET RANDOME SLOTS EVERYTIME

char **arr; // 2D ARRAY

int m,n,g;

cout<<"Enter values *(m),(n),(g): ";

cin>>m>>n>>g; // GET INPUT

arr = new char *[m]; // SET ROWS

for(int i=0;i<m;i++){

arr[i]= new char[n]; // SET COLUMNS

}

for(int i=0;i<m;i++){

for(int j=0;j<n;j++){

arr[i][j]='.'; // INTIALIZING WHOLE AS DEAD

}

}

int extraM,extraN;// EXTRA VARAS

int count=0;

for(int i=0;i<m;i++){

for(int j=0;j<n;j++){

if(count==g){ // IF IT IS EQUAL TO GENERATION BREAK THE LOOP

break;

break;

}

extraM= rand()%m; // GET RANDOME POSITIONS FOR GENERATIONS

extraN = rand()%n;

arr[extraM][extraN]='*'; // SET THEM

// cout<<"{"<<extraM<<" "<<extraN<<" }"<<endl;

count++;

}

}

for(int i=0;i<m;i++){

for(int j=0;j<n;j++){

cout<<arr[i][j]<<" "; // PRINT THE GAME

}

cout<<endl;

}

}

OUTPUT:

Enter values * (m), (n), (g): 4 + · * * . * · : · : .

IF YOU HAVE ANY QUERY PLEASE COMMENT DOWN BELOW

PLEASE GIVE A THUMBS UP